(3x-1)(x+5)=3x^2+14x-5

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Solution for (3x-1)(x+5)=3x^2+14x-5 equation: 



(3x-1)(x+5)=3x^2+14x-5

We move all terms to the left:

(3x-1)(x+5)-(3x^2+14x-5)=0

We get rid of parentheses

-3x^2+(3x-1)(x+5)-14x+5=0

We multiply parentheses ..

-3x^2+(+3x^2+15x-1x-5)-14x+5=0

We get rid of parentheses

-3x^2+3x^2+15x-1x-14x-5+5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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